\setcounter{ExampleCounter}{1}
Why do we need more than one measure of center?  Can't we just find the mean and call it a day?

\begin{example}{Comparing Mean and Median}
At a small startup, there is one CEO who takes home \$1,000,000 a year and 9 interns who make \$40,000 a year each.

\paragraph{Mean:} The average salary at this company is 
\vspace{0.25in}

\paragraph{Median:} The median salary at this company is
\vspace{0.25in}

Which of these is a better measure of what a ``typical'' member of this corporation makes?
\end{example}

This is an example of a \textbf{skewed} data set, with one outlier.

\begin{proc}{Sensitivity to Outliers}
\vspace{0.75in}
\end{proc}

The data set in that example is said to be \textbf{skewed to the right}, because the outlier is on the right, or upper side of the data set.

\pgfplotsset{width=5.75cm,compat=1.13}
\begin{center}
\begin{tabular}{c c c}
\begin{tikzpicture}
\begin{axis}[
	x tick label style={
		/pgf/number format/1000 sep=},
	enlargelimits=0.15,
	legend style={at={(0.5,-0.1)},
	anchor=north,legend columns=-1},
	ybar,
	bar width=20pt,
	ymin=1.95,
	ymax=15,
	axis lines=none,
]
\addplot +[ybar interval] plot 
	coordinates {(0,1) (1,1) (2,2)
		 (3,4) (4,6) (5,7) (6,9) (7,12) (8,15) (9,14)};
\end{axis}
\end{tikzpicture} \hspace*{0.1in}
&
\hspace*{0.1in} \begin{tikzpicture}
\begin{axis}[
	x tick label style={
		/pgf/number format/1000 sep=},
	enlargelimits=0.15,
	legend style={at={(0.5,-0.1)},
	anchor=north,legend columns=-1},
	ybar,
	bar width=20pt,
	ymin=1.95,
	ymax=15,
	axis lines=none,
]
\addplot +[ybar interval] plot 
	coordinates {(0,5) (1,8) (2,9)
		 (3,12) (4,15) (5,13) (6,10) (7,8) (8,4) (9,3)};
\end{axis}
\end{tikzpicture} \hspace*{0.1in}
&
\hspace*{0.1in} \begin{tikzpicture}
\begin{axis}[
	x tick label style={
		/pgf/number format/1000 sep=},
	enlargelimits=0.15,
	legend style={at={(0.5,-0.1)},
	anchor=north,legend columns=-1},
	ybar,
	bar width=20pt,
	ymin=1.95,
	ymax=15,
	axis lines=none,
]
\addplot +[ybar interval] plot 
	coordinates {(0,14) (1,15) (2,12)
		 (3,9) (4,7) (5,6) (6,4) (7,2) (8,1) (9,1) };
\end{axis}
\end{tikzpicture}\\
Skewed Left & Symmetric & Skewed Right\\
\\
Mean $<$ Median & Mean $\approx$ Median & Mean $>$ Median
\end{tabular}
\end{center}
\pgfplotsset{width=7cm,compat=1.13}

If the mean is larger than the median, there are outliers on the upper side pulling the mean up, so the data is skewed to the right (vice versa if the mean is smaller than the median)
\vfill
\pagebreak

\begin{example}{Skewed or Symmetric?}
Is the following data set approximately symmetric or skewed?

\begin{center}
2010 Winter Olympics Gold Medal Wins by Country\\

\begin{tabular}{c c c c c c c c c c}
0 & 0 & 1 & 1 & 1 & 1 & 2 & 2 & 2 & 3\\
4 & 4 & 5 & 5 & 6 & 6 & 9 & 9 & 10 & 14
\end{tabular}
\end{center}

\paragraph{Mean:} \text{}
\vspace{0.2in}

\paragraph{Median:} \text{}
\vspace{0.2in}

\paragraph{Conclusion:} \text{}
\vspace{1in}

\begin{center}
\begin{tikzpicture}
\begin{axis}[
	x tick label style={
		/pgf/number format/1000 sep=},
	enlargelimits=0.15,
	legend style={at={(0.5,-0.1)},
	anchor=north,legend columns=-1},
	ybar,
	bar width=20pt,
	ymin=0,
	ymax=5,
	xmin=0,
	xmax=15.5,
	axis y line=left,
	axis x line=bottom,
	xticklabels={},
	yticklabels={},
]
\addplot +[ybar interval] plot 
	coordinates {(0,2) (1,4) (2,3)
		 (3,1) (4,2) (5,2) (6,2) (7,0) (8,0) (9,2) (10,1) (11,0) (12,0) (13,0) (14,1) (15,0) };
\end{axis}
\end{tikzpicture}
\end{center}
\end{example}

Because the mean is more sensitive to outliers than the median is, the median is often a better measure of the center than the mean.  Thus, when you go shopping for a house, or looking at typical salaries in a particular field, try searching for the \emph{median} house price or salary.
\vfill
\pagebreak